Programming in C Theory and Lab EST 102 for KTU 2019 Scheme- Dr Binu V P

TYPES OF SOFTWARE Software can be broadly classified in two categories: 1. System Software, and 2. Application Software. System software provides the basic functions that are performed by the computer. It is necessary for the functioning of a computer. Application software is used by the users to perform specific tasks. The user may choose the appropriate application software, for performing a specific task, which provides the desired functionality. The system software interacts with hardware at one end and with application software at the other end. The application software interacts with the system software and the users of the computer. Figure below shows the hierarchy of software, hardware and users. System software provides basic functionality to the computer. System software is required for the working of computer itself ( operating system). The system software would also include different device drivers. When you request for using any of the devices, the corresponding device dri

 C PROGRAMMING LAB (Practical part of EST 102, Programming in C) Assessment Method: The Academic Assessment for the Programming lab should be done internally by the College. The assessment shall be made on 50 marks and the mark is divided as follows: Practical Records/Outputs - 20 marks (internal by the College),  Regular Lab Viva - 5 marks (internal by the College),  Final Practical Exam – 25 marks (internal by the College). The mark obtained out of 50 will be converted into equivalent proportion out of 20 for CIE computation. LIST OF LAB EXPERIMENTS 1. Familiarization of Hardware Components of a Computer 2. Familiarization of Linux environment – How to do Programming in C with Linux 3. Familiarization of console I/O and operators in C i) Display “Hello World” ii) Read two numbers, add them and display their sum iii) Read the radius of a circle, calculate its area and display it iv)Evaluate the arithmetic expression ((a -b / c * d + e) * (f +g)) and display its solution.Read the value